Question

5x(x-2)=<(x+1)²-10 решите срочно

Answer 1

$5x(x - 2) \leqslant ( x + 1) {}^{2} - 10$
$5x {}^{2} - 10x \leqslant x {}^{2} + 2x + 1 - 10$
$5x {}^{2} - 10x - x {}^{2} - 2x - 1 + 10 \leqslant 0$
$4x { }^{2} - 12x + 9 \leqslant 0$
$4x {}^{2} - 12x + 9 = 0$
[tex]d = b {}^{2} - 4ac = 144 - 4 \times 4 \times 9 =144-144=0
х =2