Question

Помогите пожалуйста решить

lg(x+3)
———— = 1
lg4+lg3

Answer 1

$\frac{ log_{10}(x + 3) }{ log_{10}4 + log_{10}3 } = 1 \\ \frac{ log_{10}(x + 3) }{ log_{10}(12) } = 1 \\ log_{10}(x + 3 - 12) = 1 \\ log_{10}(x - 9) = 1 \\ {10}^{1} = x - 9 \\ x = 19$