Question

Докажите тождество (p+1)(p+1)(p+1)=p³+3p²+3p+1

Answer 1

$\(p+1)(p+1)(p+1)=p^3+3p^2+3p+1\ (p+1)^3=p^3+3p^2+3p+1\ p^3+3p^2+3p+1=p^3+3p^2+3p+1$

 

использую:

$\(a+b)^3=a^3+3a^2b+3ab^2+b^3$

Answer 2

(p+1)(p+1)(p+1)=p³+3p²+3p+1

(p+1)³ = p³+3p²+3p+1

p³+3p²+3p+1 = p³+3p²+3p+1