Question

Помогите решить, пожалуйста.
$\frac{11x-4}{5}=\frac{x^{2}}{2}$

Answer 1

$2(11x - 4) = 5x {}^{2}$

$2(11x - 4) - 5x {}^{2} = 0$

$22x - 8 - 5x {}^{2} = 0$

$- 22x + 8 + 5x {}^{2} = 0$

$5x {}^{2} - 2x - 20x + 8 = 0$

$x \times (5x - 2) - 4(5x - 2) = 0$

$(5x - 2) \times (x - 4) = 0$

$5x - 2 = 0 \\ x - 4 = 0$

$x = \frac{2}{5} \\ x = 4$

Answer 2

$2(11x-4)=5x^2\\22x-8=5x^2\\5x^2-22x+8=0\\D=(-22)^2-4*5*8=484-160=324\\x_1=\frac{-(-22)+\sqrt{324}}{2*5}=\frac{22+18}{10}=4\\ x_2=\frac{-(-22)-\sqrt{324}}{2*5}=\frac{22-18}{10}=\frac{4}{10}=0.4$