Question

3x^2-14x+16>0
5x^2-16x+3<0
x^2+2x-80 больше или равно 0
3x^2+32x+80<0​

Answer 1

3x^2-14x+16>0

3x^2-6x-8x+16>0

3x(x-2)-8(x-2)>0

(x-2)(3x-8)>0

$\left \{ {{x-2>0} \atop {3x-8>0}} \right.$

$\left \{ {{x-2<0} \atop {3x-8<0}} \right.$

$\left \{ {{x>2} \atop {x>\frac{8}{3} }$

$\left \{ {{x<2} \atop {x<\frac{8}{3} }} \right.$

x∈(-∞; 2)∪(8/3; +∞)