Question

Выделите целую часть дроби 9/13+7/52 ; 5/42+3/14 ; 5/17+2/51 ; 17/36+5/18. Помогите срочно!

Answer 1

9/13+7/52=(9×4)/(13×4)+7/52=36/52+7/52=(36+7)/52=43/52

5/42+3/14=5/42+(3×3)/(14×3)=5/42+9/42=14/42=1/3

5/17+2/51=(5×3)/(17×3)+2/51=15/51+2/51=17/51=1/3

17/36+5/18=17/36+(5×2)/(18×2)=17/36+10/36=27/36=3/4