Question

14 корней из 2(sin^4 3п/8*cos^4 3п/8)

Answer 1

$14\sqrt{2}(sin^4\frac{3\pi }{8}-cos^4\frac{3\pi }{8})=14\sqrt{2}(sin^2\frac{3\pi }{8}-cos^2\frac{3\pi }{8})(sin^2\frac{3\pi }{8}+cos^2\frac{3\pi }{8})=\\=14\sqrt{2}*(-cos\frac{3\pi }{4})=14\sqrt{2}*cos\frac{\pi }{4}=14\sqrt{2}*\frac{\sqrt{2}}{2}=14$

УДАЧИ ВАМ И УСПЕХОВ)))!!!

Answer 2

$14\sqrt{2}(Sin^{4}\frac{3\pi }{8}-Cos^{4} \frac{3\pi }{8})=14\sqrt{2}(Sin^{2}\frac{3\pi }{8}+Cos^{2}\frac{3\pi }{8})(Sin^{2}\frac{3\pi }{8}-Cos^{2} \frac{3\pi }{8})=14\sqrt{2}*1*(-Cos\frac{3\pi }{4})=-14\sqrt{2}Cos(\pi-\frac{\pi }{4} )=14\sqrt{2}Cos\frac{\pi }{4}=14\sqrt{2}*\frac{1}{\sqrt{2} } =14$