Question

-0.5x^2×y(-2x^2+4y+4xy^2)

Answer 1

$- 0.5 {x}^{2}y \times ( - 2 {x}^{2} + 4y + 4x {y}^{2}) = \\ = {x}^{4}y - 2 {x}^{2} {y}^{2} - 2 {x}^{3} {y}^{3} .$