Question

вычислите пожалуйста!

Answer 1

$\sqrt{3}Ctg(2arcCos(-\frac{\sqrt{3} }{2})-\frac{\pi }{2})=\sqrt{3}Ctg(2* \frac{5\pi }{6}-\frac{\pi }{2})=\sqrt{3} Ctg(\frac{5\pi }{3}-\frac{\pi }{2})=\sqrt{3}Ctg\frac{7\pi }{6}=\sqrt{3}Ctg(\pi+\frac{\pi }{6} )=\sqrt{3}Ctg\frac{\pi }{6}=\sqrt{3}*\sqrt{3}=3$