Question

cd+d^2/6•12/(c+d) при c=1, d=2
(2a/1+a + 1/a):a/1+a=

Answer 1

$\frac{cd+d^{2} }{6}$ · $\frac{12}{c+d}$

$\frac{1·2+[tex]2^{2}$}{6}[/tex]·$\frac{12}{1+2}$=$\frac{2+4}{6}$·$\frac{12}{3}$=$\frac{6}{6}$·$\frac{12}{3}$=1·$\frac{12}{3}$=$\frac{12}{3}$=4