Question

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Answer 1

$\frac{(Sin(-\alpha)+Cos(-\alpha))^{2} -1}{-Sin(-\alpha) }=\frac{(Cos\alpha-Sin\alpha )^{2}-1}{Sin\alpha }=\frac{Cos^{2}\alpha -2Sin\alpha Cos\alpha+Sin^{2}\alpha -1 }{Sin\alpha }=\frac{1-2Sin\alpha Cos\alpha-1}{Sin\alpha }=\frac{-2Sin\alpha Cos\alpha}{Sin\alpha }=-2Cos\alpha$