Question

Пожалуйста, помогите

Answer 1

Ответ:

Пошаговое объяснение:

1)

$\dfrac{32^{n+1}\times 9^n}{3^{2n-1}\times 2^{5n}}= \dfrac{2^{5n+5}\times 3^{2n}}{3^{2n-1}\times 2^{5n}}=2^{5n+5-5n}\times 3^{2n-2n+1}=2^5\times3=96$

2)

$\dfrac{20^{n+2}}{2^{2n-1}\times 5^{n+3}} =\dfrac{2^{2n+4}\times 5^{n+2}}{2^{2n-1}\times 5^{n+3}} =2^{2n+4-2n+1}\times 5^{n+2-n-3}=2^5\times 5^{-1}=\dfrac{32}{5} =6,4$

3)

$\dfrac{2x}{3} -\dfrac{4x-1}{4} =5-\dfrac{2x-7}{24} \\\\8*2x-6(4x-1)=120-(2x-7)\\\\16x-24x+6=120-2x+7\\\\8x-2x=6-127\\\\6x=-121\\\\x=-\dfrac{121}{6} =-20\dfrac{1}{6}$

4)

$4x^3-3x-1=0\\\\4x^3-4x^2+4x^2-3x-1=0\\\\4x^2(x-1)+4x(x-1) +4x - 3x - 1= 0\\\\(x-1)(4x^2+4x+1)=0\\\\(x-1)(2x+1)^2=0\\\\x_1=1\\\\x_{2,3}=-0,5$