Question

помогите пж, назавтра очень надо.​

Answer 1

$\displaystyle log_{1/2}(9-4x)-log_{1/2}\frac{1}{3}=log_{1/2}15\\\\ODZ:x<9/4\\\\log_{1/2}\frac{9-4x}{1/3}=log_{1/2}15\\\\3(9-4x)=15\\\\9-4x=5\\\\4x=4\\\\x=1$