Question

50 баллов!
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Answer 1

f(x) = Cosx - Sinx

f'(x) = (Cosx)' - (Sinx)' = - Sinx - Cosx

$1)f'(x_{o})=f'(\frac{\pi }{2})=-Sin\frac{\pi }{2} -Cos\frac{\pi }{2}=-1-0=-1\\\\2)f'(x_{o})=f'(\pi)=-Sin\pi - Cos\pi=-0.(-1)=1$