Question

решите пожалуйста систему уравнение
4x^2+y=9
8x^2-y=3

Answer 1

$y = 9 - 4 {x}^{2}$
$8 {x}^{2} - (9 - 4 {x}^{2} ) = 3$

$y = 9 - 4 {x}^{2}$
$8 {x}^{2} - 9 + 4 {x}^{2} - 3 = 0$

$y = 9 - 4 {x}^{2}$
$12 {x}^{2} - 12 = 0$

$y = 9 - 4 {x}^{2}$
${x}^{2} - 1 = 0$

$y = 9 - 4 {x}^{2}$
${x}^{2} = 1$

$x1 = 1$
$y1 = 9 - 4 \times 1$

$x1 = 1$
$y1 = 5$

$x2 = - 1$
$y2 = 9 - 4 \times ( - 1)$

$x2 = - 1$
$y2 = 13$

Ответ: (1;5); (-1;13)