Question

4 - 1 целая 9/16 х во 2 =0​

Answer 1

$4-1\frac{9}{16}x^{2}=0\\\\4-\frac{25}{16}x^{2}=0\\\\2^{2}-(\frac{5}{4}x)^{2} =0\\\\(2-\frac{5}{4}x)(2+\frac{5}{4}x)=0\\\\1)2-\frac{5}{4} x=0\\\\\frac{5}{4}x=2\\\\x_{1} =\frac{8}{5}=1,6 \\\\2)2+\frac{5}{4}x=0\\\\\frac{5}{4}x=-2\\\\x_{2} =-\frac{8}{5} =-1,6$