Предмет: Алгебра, автор: mozggolovnoj

Прошу помогите пожалуйста

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Автор ответа: alesyaperova
0

 1){x}^{2} - 26x + 133 = 0 \\ d = 676 - 532 = 144 = 12 \\ x1 =  \frac{26 - 12}{2}  =  \frac{14}{2}  = 7

x2 =  \frac{26 + 12}{2}  =  \frac{38}{2}  = 19

x1 + x2 = 7 + 19 = 26

x1 \times x2 = 7 \times 19 = 133

2) {x}^{2}  - 7x  - 30 = 0 \\ d = 49 + 120 = 169 = 13 \\ x1 =  \frac{7 - 13}{2}  =  -  \frac{6}{2}  =  - 3

x2 =  \frac{7 + 13}{2}  =  \frac{20}{2}  = 10

x1 + x2 =  - 3 + 10 = 7 \\ x1 \times x2 =  - 3 \times 10 =  - 30

3) {x}^{2}  - 18x + 45 = 0 \\ d = 324 - 180 = 144 = 12 \\ x1 =  \frac{18 - 12}{2}  =  \frac{6}{2}  = 3

x2 =  \frac{18 + 12}{2}  =  \frac{30}{2}  = 15

x1 + x2 = 3 + 15 = 18 \\ x1 \times x2 = 3 \times 15 = 45

4)

 {x}^{2}  - 12x - 28 = 0 \\ d = 144 + 112 = 256 = 16 \\ x1 =  \frac{12 - 16}{2}  =  -  \frac{4}{2}  =  - 2

x2 =  \frac{12 + 16}{2}  =  \frac{28}{2}  = 14

x1 + x2 =  - 2 + 14 = 12 \\ x1 \times x2 =  - 2 \times 14 =  - 28

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