Question

помогите сделать в левой части полный квадрат

Answer 1

4x² + 3x = 1

$(x^{2} +\frac{3}{4}x+\frac{9}{64})-\frac{9}{64}=\frac{1}{4}\\\\(x+\frac{3}{8})^{2} =\frac{1}{4}+\frac{9}{64}\\\\(x+\frac{3}{8})^{2}=\frac{25}{64}\\\\1)x+\frac{3}{8}=-\frac{5}{8}\\\\x_{1}=-\frac{5}{8}-\frac{3}{8}=-1\\\\2)x+\frac{3}{8} =\frac{5}{8} \\\\x_{2}=\frac{5}{8}-\frac{3}{8}=\frac{2}{8}=0,25$