Question

можете решить, расписав?
√3/2cosx+1/2sinx=1

Answer 1

$\frac{\sqrt{3} }{2}Cosx+\frac{1}{2}Sinx=1\\\\Cos\frac{\pi }{6}Cosx+Sin\frac{\pi }{6}Sinx=1\\\\Cos(\frac{\pi }{6}-x)=1\\\\\frac{\pi }{6}-x=2\pi n,n\in z\\\\x=\frac{\pi }{6}+2\pi n,n\in z$