Question

b 2x+78=10 4x+5b=12​

Answer 1

2x+78=10
2x=10-78
X= -34

4x+5b=12

Answer 2

Дано:

$\bf 1) \tt 2x+78=10 \\ \bf 2) \tt 4x + 5b = 12$

Решение:

$\bf 1) \tt 2x + 78 = 10 \\ \tt 2x=10-78 \\ \tt 2x=-68 \\ \tt x=-68 \div 2 \\ \bf x=-34$

$\bf 2) \tt 4x+5b=12 \\ \tt 4x=12-5b \\ \bf x=3-\frac{5}{4}b$

$\boxed{\bf OTBET: x_1=-34; \: \: x_2=3-\frac{5}{4}b}$