Question

РЕШИТЬ УРАВНЕНИЯ (29-х0+(3Х-16)= след.115-(7Х-3)-(100-8Х)= след.23х-(2х-17)-(29+8)= след 29-(3Х-11)-(43-7х)+(169-14Х)-(39-8)=

Answer 1

(29-х0+(3Х-16)=29-0+3х-16=3х+13

3х=-13

х=-13/3

х=-4 1/3

115-(7Х-3)-(100-8Х)=115-7х+3+100+8х=х+218

х=-218

23х-(2х-17)-(29+8)=23х-2х+17-37=21х-20

21х=20

х=20/21

29-(3Х-11)-(43-7х)+(169-14Х)-(39-8)=29-3х+11+43+7х+169-14х-31=221-10х

-10х=-221

х=221/10

х=22,1