Question

сократить дробь

$\frac{(x-3)^2 -2}{x^2-1}$

Answer 1

$\displaystyle \frac{(x-3)^2-2}{x^2-1}=\frac{x^2-6x+9-2}{x^2-1}=\frac{x^2-6x+7}{x^2-1}=\frac{x^2-1-6x+8}{x^2-1}=\\\\\\=\boxed{1-\frac{6x-8}{x^2-1}}$