Question

Помогите решить :
${y}^{2} - (7y - 6)^{2} = 0$
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Answer 1

$y^2-(7y-6)^2=0\\(y-7y+6)(y+7y-6)=0\\(-6y+6)(8y-6)=0\\\\-6y+6=0\\6y=6\\y_1=1\\\\8y-6=0\\8y=6\\y_2=\frac{3}{4}$