Question

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Answer 1

$(4-\sqrt{24})x>40-8\sqrt{24}\ /:(4-\sqrt{24})\\\\x<\frac{40-8\sqrt{24}}{4-\sqrt{24}}\\\\x<\frac{(40-8\sqrt{24})(4+\sqrt{24})}{(4-\sqrt{24})(4+\sqrt{24})}\\\\x<\frac{160+40\sqrt{24}-32\sqrt{24}-192}{16-24}\\\\x<\frac{-32+8\sqrt{24}}{-8}\\\\x<\frac{-8(4-\sqrt{24})}{-8}\\\\x<4-\sqrt{24}\\\\x<4-2\sqrt{6}\\\\\\4-2\sqrt6\approx-0,9$

Ответ: - 1