Question

Хелп а и б
....................

Answer 1

Ответ:

Пошаговое объяснение:

$\sqrt{3\frac{1}{16} }-5*\sqrt{1,44}= \sqrt{\frac{49}{16} }-\sqrt{25}*\sqrt{1,44}=\frac{7}{4}-\sqrt{25 * 1,44}=\frac{7}{4}-\sqrt{36} =\frac{7}{4}-6=\frac{7-24}{4}=-\frac{17}{4}=-4,25$

$\sqrt{72}:\sqrt{2}=\sqrt{72 : 2}=\sqrt{36}=6$

$\sqrt{3\frac{1}{3} }*\sqrt{7,5}=\sqrt{\frac{10}{3} }*\sqrt{\frac{75}{10} }=\sqrt{\frac{10}{3}*\frac{75}{10}}=\sqrt{25}=5$

Answer 2

а)

$......=\sqrt{\frac{49}{16} } -5\sqrt{\frac{144}{100} } =\frac{7}{4} -5*\frac{12}{10} =1,75-6=-4,25$

б)

$........=\sqrt{\frac{10}{3} } *\sqrt{\frac{75}{10} } =\sqrt{\frac{10*75}{3*10} } =\sqrt{25} =5$