Question

Помогите пожалуйста

Answer 1

tg(pi+t)=tg(t)
sin(6pi+t)=sin(t)
$\cos(t ) = \sqrt{1 - \sin(t) {}^{2} }$
$\cos(t) = \frac{5}{13}$
$\tan(t) = \frac{ \sin(t) }{ \cos(t) }$
$\tan(t) = \frac{12}{13} \div \frac{5}{13} = \frac{12}{5} = 2.4$

Answer 2

tg(pi+t)=tg(t)

sin(6pi+t)=sin(t)

\cos(t ) = \sqrt{1 - \sin(t) {}^{2} }

\cos(t) = \frac{5}{13}

\tan(t) = \frac{ \sin(t) }{ \cos(t) }

\tan(t) = \frac{12}{13} \div \frac{5}{13} = \frac{12}{5} = 2.4