Question

16^log ₇ 98/16^log ₇2

Answer 1

$\frac{16^{log_{7}98 } }{16^{log_{7}2 } }=\frac{16^{(log_{7}49+log_{7}2)}}{16^{log_{7}2}}=\frac{16^{2}*16^{log_{7}2 }}{16^{log_{7}2}}=16^{2}=256$