Question

решите уравнение (x+3)(x^2-3x+9)=x^3-3x​

Answer 1

(x + 3) (x^2 - 3 x + 9) = x^3 - 3 x

3 x + 27 = 0

x^3 + 27 = x (x^2 - 3)

(x + 3) (x^2 - 3 x + 9) = x (x^2 - 3)

x^3 + 27 = x^3 - 3 x

x = -9

Answer 2

$(x+3)(x^{2} -3x+9)=x^{3} -3x\\x^{3}+27=x^{3} -27=-3x\\ -9=x$