Question

Решите пожалуйста там 3 задания.)

Answer 1

1) $\frac{15a - 10b}{200b - 300a} = \frac{15a - 10b}{ - 20( - 10b + 15a)} = - \frac{1}{20}$
2)
$18x - 6x {}^{2} = 0 \\ 6x(3 - x) = 0 \\ x1 = 0 \\ 3 - x = 0 \\ - x = - 3 \\ x2 = 3$
3)
$(4 {x}^{2} + 3x - 7) - (3x {}^{2} + x - 8) = x {}^{2} + 2x + 1$