Question

Знайти x якщо:
$\frac{log_{9} 27+log_{9}3}{2log_{2}6-log_{2}9}$

Answer 1

$\frac{log_{9} 27+log_{9}3}{2log_{2}6-log_{2}9}=\frac{log_{9} (27\cdot3)}{log_{2}6^2-log_{2}9}=\frac{log_{9} 81}{log_{2}36-log_{2}9}=\frac{log_{9} 9^2}{log_{2}(36:9)}=\\\\\frac{2log_{9} 9}{log_{2}4}=\frac{2}{log_{2}2^2}=\frac{2}{2log_{2}2}=\frac{2}{2}=1$