Question

9^3/2 +27^2/3 - (1/16)^3/4

Answer 1

$\frac{9 {}^{3} }{2} + \frac{27 {}^{2} }{3} - ( \frac{1}{16} ) {}^{ \frac{3}{4} }$

$\frac{729}{2} + \frac{27 {}^{2} }{3} - \sqrt[4]{( \frac{1}{6} } ) {}^{3}$

$\frac{729}{2} + \frac{27 {}^{3} }{3} - 2 {}^{ - 3}$

$\frac{729}{2} + \frac{27 {}^{2} }{3} - \frac{1}{8}$

$\frac{4859}{8}$

$607 \frac{3}{8}$