Question

найти производную
даю 20 за скорость))​

Answer 1

$y {}^{'} = ( \frac{ \cos(5x) }{ {x}^{2} } ) {}^{'} = \frac{ {x}^{2} \times ( \cos(5x) ) {}^{'} - \cos(5x) \times 2x}{ {x}^{4} } = \frac{ - 5{x}^{2} \times \sin(5x) - 2x \cos(5x) }{ {x}^{4} }$