Question

Помогите решить
2sin^2x - 5sinxcosx=0​

Answer 1

6+tg^2x-5tgx=0

tg^2x-5tgx+6=0

D=25-24=1(1)

tgx1=(5+1)/2=3

tgx2=(5-1)/2=2

x1=arctg3+Пn

x2=arctg2+Пn