Question

x²-2x+1/x³-x²-x+1 x=1 ⅔

Answer 1

$\frac{x^2-2x+1}{x^3-x^2-x+1}=\frac{(x-1)^2}{x^2(x-1)-(x-1)} =\frac{x-1}{(x-1)(x+1)}=\frac{1}{x+1}=>\frac{3}{8}$