Question

Разложите на множители:
12а³х-36а²bх+27ab²х
2а²b³-28ab²+98b

Answer 1

$1)12 {a}^{3} x - 36 {a}^{2} bx + 27a {b}^{2} x = 3ax \times (4 {a}^{2} - 12ab + 9 {b}^{2} ) = 3ax \times (2a - 3b)^{2} \\ 2)2{a}^{2} {b}^{3} - 28a {b}^{2} + 98b = 2b \times ( {a}^{2} {b}^{2} - 14ab + 49) = 2b \times (ab - 7)^{2}$