Question

ПОМОГИТЕ РЕШИТЬПЖ! при х=-0,12 при y=0,5

Answer 1

$\frac{ \frac{1}{ {x}^{2} } - \frac{1}{ {y}^{2} } }{ \frac{1}{x} - \frac{1}{y} } \times \frac{ {x}^{2} {y}^{2} }{ x + y} = \\ ( (\frac{ {y}^{2} - {x}^{2} }{ {x}^{2} {y}^{2} } ) \div ( \frac{y - x}{x y} )) \times \frac{ {x}^{2} {y}^{2} }{ x+ y} = \\ ( \frac{(y - x)(y + x)}{ {x}^{2} {y}^{2} } \times \frac{xy}{y - x} ) \times \frac{ {x}^{2} {y}^{2} }{ x+ y} = \\ \frac{y + x}{xy} \times \frac{ {x}^{2} {y}^{2} }{x + y} = xy$
x=-0.12, y=0.5
xy=-0.12×0.5=-0.06

Answer 2

на фото..............