Question

ПОМОГИТЕ СРОЧНО!!!
$3y^{2} + 4y = 0$
$3 - 12x^{2} = 16x$
​

Answer 1

$3y^{2}+4y=0\\ y(3y+4)=0\\\\\left \{ {{y=0} \atop {3y=-4}} \right. \\\left \{ {{y=0} \atop {y=-\frac{4}{3} }} \right.$

$3-12x^{2} =16x\\12x^{2} +16x-3=0\\D/4=k^{2}-ac=64+36=100\\\left \{ {{x=\frac{1}{6} } \atop {x=-\frac{3}{2} }} \right.$