Question

$1) (a+7)^{2}=\\ 2)(3x-4y)^{2}=\\3)(m-6)(m+6)=\\4)(5a+8b)(8b-5a)=\\\\5)a^{2}-9=\\ 6)b^{2} +10b+25=\\7)25x-16=\\8)9x^{2}-12xy+4y^{2} =\\ \\9)(x-1)^{2}-(x+3)(x-3)=\\ 10)(a+1)(a-1)(a^{2}+1)-9+a^{2})^{2}=$


пж помогите по теме формулы сокращённого умножения даю 50 баллов

Answer 1

$(a + 7) {}^{2} = a {}^{2} + 14a + 49 \\ (3x - 4y) {}^{2} = 9x {}^{2} - 24xy + 16y {}^{2} \\ (m - 6)(m + 6) = m {}^{2} - 36 \\ (5a + 8b)(8b - 5a) = 64b {}^{2} - 25a {}^{2}$

$a {}^{2} - 9 = (a - 3)(a + 3) \\ b {}^{2} + 10b + 25 = (b + 5) {}^{2}$

$9x {}^{2} - 12xy + 4y {}^{2} = (3x - 2y) {}^{2}$

$(x - 1) {}^{2} - (x + 3) (x - 3) = - 2x + 10$

$(a + 1)(a - 1)(a {}^{2} + 1) - 9 = a {}^{4} + 8$