Question

Ребят помогите пожалуйста!!!!!!​

Answer 1

$\frac{4}{6 - x} + 6 - x + 4 = 0 \\ \frac{4 + 6(6 - x) - x(6 - x) + 4(6 - x)}{6 - x} = 0 \\ 4 + 36 - 6x - 6x + {x}^{2} + 24 - 4x = 0 \\ {x}^{2} - 16x + 64 = 0 \\ (x - 8)^{2} = 0 \\ x = 8$