Question

Разложи на множотели

Y^2-100=

Y^2-0,16x^2=

a^4-25=

8x^2-8y^2=

27x^3-1=

Answer 1

$y^2-100=(y-10)(y+10)\\y^2-0,16x^2=(y-0,4x)(y+0,4x)\\a^4-25=(a^2-5)(a^2+5)=(a-\sqrt5)(a+\sqrt5)(a^2+5)\\8x^2-8y^2=8(x^2-y^2)=8(x-y)(x+y)\\27x^3-1= (3x)^3-1=(3x-1)(9x^2+3x+1)$

Answer 2

$1.(y - 10)(y + 10) \\ 2.(y - 0.4x)(y + 0.4x)$

$3.( {a}^{2} - 5)( {a}^{2} + 5)$

$4. (\sqrt{8} x - \sqrt{8} y)( \sqrt{8} x + \sqrt{8} y)$

$5.(3x - 1)(9 {x}^{2} + 3x + 1)$