Question

Помогите пожалуйста ❤️
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Answer 1

$(4x + 1) {}^{2} - 2x \times (8x - 1) = 0 \\ 16x {}^{2} + 8x + 1 - 16x {}^{2} + 2x = 0 \\ 10x - + 1 = 0 \\ 10x = - 1 \\ x = - \frac{1}{10}$