Question

1,2-формулы
3-решить

Answer 1

$1) {25x}^{2} + 70x + 49$

$2) {4m}^{2} + 4m + 1 - 16 {m}^{2} = \\ - 12 {m}^{2} + 4m + 1$

$3)0.04 {y}^{2} - 4y + 100 = 0 | \div 0.04| \\ {y}^{2} - 100y + 2500 = 0 \\ (y - 50) {}^{2} = 0 \\ y - 50 = 0 \\ y$

$y = 50$