Question

решите уравнение !!!!!​

Answer 1

а)5*2=10x

x=10-5

x=5

5x+5=0

Answer 2

a)

$5x^2+x=0\\ x(5x+1)=0\\ \\ \left \{ {{x_1=0} \atop {5x+1=0}} \right. =>\left \{ {{x_1=0} \atop {x_2=-\frac{1}{5} }} \right.$

б)

$(6-3x)^2=4x-8\\36-36x+9x^2-4x+8=0\\ 44-40x+9x^2=0\\ 9x^2-40x+44=0\\ 9x^2-18x-22x+44=0\\ 9x(x-2)-22(x-2)=0\\(x-2)(9x-22)=0\\\\\left \{ {{x-2=0} \atop {9x-22=0}} \right. =>\left \{ {{x_1=2} \atop {x_2=\frac{22}{9} }} \right.$

можно было решить дискриминантом

в)

$2x^3-10x^2+3x-15=0\\2x^2(x-5)+3(x-5)=0\\(x-5)(2x^2+3)=0\\\\x-5=0\\x_1=5\\\\2x^2=-3\\x \in \emptyset\\\\x=5$