Question

Решите уравнение (x+3)(4x-1)-4(x+3)^2=13.

Answer 1

4x^2-x+12x-3-4(x^2+6x+9)-13=0

4x^2-x+12x-3-4x^2-24x-36-13=0

-13x-52=0

-13x=52

x=52/(-13)

x=-4

Answer 2

(х+3)(4х-1-4х-12)=13

(х+3)(-13)=13

х+3=-1; х=-4.