Question

Помогите с последним примером, в файле

Answer 1

$\frac{1}{x-5} +\frac{1}{x+3} =0\\\\\frac{1(x+3)+1(x-5)}{(x-5)(x+3)} =0\\\\\frac{x+3+x-5}{(x-5)(x+3)} =0\\\\\frac{2x-2}{(x-5)(x+3)} =0\\\\1)ODZ:\\\\x-5\neq 0\\x\neq 5\\\\x+3\neq 0\\x\neq -3\\\\2)2x-2=0\\2x=2|:2\\x=1\\\\Otvet:1$

Answer 2

(х+3+х–5)/(х–5)(х+3) = 0
(2х–2)/(х–5)(х+3)=0
2х–2=0; (х–5)(х+3)#0
х=1. х#5; х#–3