Question

Буду очень благодарен)

Answer 1

1)

$3x( {x}^{2} - 4) = 0 \\ 3x(x - 2)(x + 2) = 0 \\ x1 = 0 \\ x2 = 2 \\ x3 = - 2$

2)

$x(49 {x}^{2} + 14x + 1) = 0 \\ x(7x + 1 ) = 0 \\ x1 = 0 \\ 7x + 1 = 0 \\ 7x = - 1 \\ x2 = - \frac{1}{7}$

3)не знаю, сорри