Question

72/73*34/65+72/73*39/65

Answer 1

Решение:

$\displaystyle \[\frac{{72}}{{73}}*\frac{{34}}{{65}}+\frac{{72}}{{73}}*\frac{{39}}{{65}}=\frac{{72}}{{73}}*\left( {\frac{{34}}{{65}}+\frac{{39}}{{65}}} \right)=\frac{{72}}{{73}}*\frac{{73}}{{65}}=\frac{{72}}{{65}}=1\frac{7}{{65}}\]$

Answer 2

$\displaystyle \tt \frac{72}{73}\cdot\frac{34}{65}+\frac{72}{73}\cdot\frac{39}{65}=\frac{2448}{4745}+\frac{2808}{4745}=\frac{5256}{4745}=\frac{5256\div73}{4745\div73}=\frac{72}{65}=\bold{1\frac{7}{65}}$