Question

(7√3+14√48-√147):2√3
ответ :28

Answer 1

$(7 \sqrt{3} + 14 \sqrt{48} - \sqrt{147} ) \div 2 \sqrt{3}$

$(7 \sqrt{3} + 14 \sqrt{16 \times 3} + \sqrt{49 \times 3} ) \div 2 \sqrt{3}$

$(7 \sqrt{3} + 56 \sqrt{3} - 7 \sqrt{3} ) \div 2 \sqrt{3}$

$56 \sqrt{3} \div 2 \sqrt{3} = 28$