Question

вычислите: 3sin p/2+4cos2p/3+6sin13p/6​

Answer 1

$3sin(\frac{\pi }{2} )+4cos(\frac{2\pi }{3} )+6sin(\frac{13\pi }{6} )= 3*1+4(-\frac{1}{2} )+6*\frac{1}{2}= 3-2+3= 4$