Question

Решите, с меня 15 б вот

Answer 1

$3 \sqrt{ \frac{36}{25} } - 1 = 3 \times \frac{6}{5} - 1 = \frac{18}{5} - 1 = \frac{13}{5} = 2 \times \frac{3}{5}$

$\sqrt{0.75} \times \sqrt{0.3} = \sqrt{0.75 \times 0.3} = \sqrt{0.225} = 15 \sqrt{0.001}$

$\frac{ \sqrt{250} }{ \sqrt{10} } = \sqrt{ \frac{250}{10} } = \sqrt{25} = 5$

$\sqrt{ {5}^{4} \times {2}^{6} } = {5}^{2} \times {2}^{3} = 25 \times 8 = 200$

задание 2.

$2 \sqrt{128} - \sqrt{72} = 2 \sqrt{64 \times 2} - \sqrt{9 \times 4 \times 2} = 2 \times 8 \sqrt{2} - 3 \times 2 \sqrt{2} = 16 \sqrt{2} - 6 \sqrt{2} = 10 \sqrt{2}$

$(3 \sqrt{2} + \sqrt{50} ) \sqrt{2} = (3 \sqrt{2} + 5 \sqrt{2} ) \sqrt{2} = 8 \sqrt{2} \times \sqrt{2} = 16$

${(6 - \sqrt{3} )}^{2} = 36 - 12 \sqrt{3} + 9 = 45 - 12 \sqrt{3} = 3(15 - 4 \sqrt{3} )$

задание 3.

$12 \sqrt{3} = \sqrt{144 \times 3} = \sqrt{432} \\ - 8 \sqrt{5} = \sqrt{64 \times 5} = \sqrt{320}$

$\sqrt{ {a}^{2} - 12a + 36 } = \sqrt{ {(a - 6)}^{2} } = a - 6 \\ a = 5.9 = > a - 6 = 5.9 - 6 = - 0.1$